Termination w.r.t. Q of the following Term Rewriting System could not be shown:

Q restricted rewrite system:
The TRS R consists of the following rules:

f3(x, y, z) -> g3(x, y, z)
g3(0, 1, x) -> f3(x, x, x)

Q is empty.


QTRS
  ↳ Non-Overlap Check

Q restricted rewrite system:
The TRS R consists of the following rules:

f3(x, y, z) -> g3(x, y, z)
g3(0, 1, x) -> f3(x, x, x)

Q is empty.

The TRS is non-overlapping. Hence, we can switch to innermost.

↳ QTRS
  ↳ Non-Overlap Check
QTRS
      ↳ DependencyPairsProof

Q restricted rewrite system:
The TRS R consists of the following rules:

f3(x, y, z) -> g3(x, y, z)
g3(0, 1, x) -> f3(x, x, x)

The set Q consists of the following terms:

f3(x0, x1, x2)
g3(0, 1, x0)


Q DP problem:
The TRS P consists of the following rules:

G3(0, 1, x) -> F3(x, x, x)
F3(x, y, z) -> G3(x, y, z)

The TRS R consists of the following rules:

f3(x, y, z) -> g3(x, y, z)
g3(0, 1, x) -> f3(x, x, x)

The set Q consists of the following terms:

f3(x0, x1, x2)
g3(0, 1, x0)

We have to consider all minimal (P,Q,R)-chains.

↳ QTRS
  ↳ Non-Overlap Check
    ↳ QTRS
      ↳ DependencyPairsProof
QDP

Q DP problem:
The TRS P consists of the following rules:

G3(0, 1, x) -> F3(x, x, x)
F3(x, y, z) -> G3(x, y, z)

The TRS R consists of the following rules:

f3(x, y, z) -> g3(x, y, z)
g3(0, 1, x) -> f3(x, x, x)

The set Q consists of the following terms:

f3(x0, x1, x2)
g3(0, 1, x0)

We have to consider all minimal (P,Q,R)-chains.